(2x-5)^2-(2x+3)(2x-3)=0

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Solution for (2x-5)^2-(2x+3)(2x-3)=0 equation: 



(2x-5)^2-(2x+3)(2x-3)=0

We use the square of the difference formula

4x^2+(2x-5)^2+9=0

We move all terms containing x to the left, all other terms to the right

4x^2+(2x-5)^2=-9

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